3493. Properties Graph

解題說明

C++ 解法

複雜度分析

虛擬碼

1. Initialize Union-Find with n nodes
2. For each node i, convert properties[i] to a hash set
3. For each pair (i, j) where i < j:
   a. Count common elements between sets[i] and sets[j]
   b. If common >= k, union(i, j)
4. Count distinct roots in Union-Find
5. Return the count of connected components

其他解法

延伸思考